Hi everyone! I have been trying to understand how Fift interpreter and compiler work since yesterday.

I don't understand how active words work.

Doc says "New active words are defined similarly to new ordinary words, but using “::”
instead of “:”. For instance, { bl word 1 ’ type } :: say"

1 2 say hello + .
will print “hello3 ok”, while

Could anyone tell me how it works step by step?

I understand it like the folllowing:
Interpreter push 1 2 to the stack, after that it finds "say" word, it's active and state = 0, then it executes immediately -> "1" Object{0x60000324dcc0}. The stack stores 1 2 "1" Object{0x60000324dcc0}. Next "hello" and I expect that it throws an exception, but it doesn't happen, it adds 1 to 2 instead. And before Addition it adds "hello" and removes "1".

How does it work? Help me please